creation of toeplitz matrix

Good morinig,

i have a cell matrix ( 6 x 1 ) where inside each cell i have a vector of two values. I would like to get a toeplitz matrix and I tried to use the command toeplitz(c,r) but I got the following error 'Inputs must be numeric'. In fact inside each cell I don't have a single value but a vector of two values.

What can i do? thanks

Answer 1

[Star Strider]

It would help to see the code, since I have no idea what ‘r’ is.

That aside, try something like this —

cell_matrix = {rand(1,2); rand(1,2); rand(1,2)}

cell_matrix = 3×1 cell array
    {[0.8842 0.4232]}
    {[0.5807 0.8143]}
    {[0.9432 0.7645]}

r = rand(1,2)

r = 1×2

0.7594 0.9229

tm = toeplitz([cell_matrix{:}], r)

Warning: First element of input column does not match first element of input row.
Column wins diagonal conflict.

tm = 6×2

0.8842 0.9229 0.4232 0.8842 0.5807 0.4232 0.8143 0.5807 0.9432 0.8143 0.7645 0.9432

This indexing convention extracts the data in the comma-separated list of the cell array and concatenates it, creating a numeric vector. I have no idea if that numeric vector is the desired one. Another option is the cell2mat function.

See Access Data in Cell Array for more details.

.

[g]

what I mean is that I have:

cell_matrix = 
{[0.9503 0.5174]}
{[0.2850 0.6280]}
{[0.4221 0.3325]}

And from this array I want to get the toeplitz matrix:

toeplitz_matrix=
[0.9503 0.5174] [0 0 ][0 0 ]
[0.2850 0.6280] [0.9503 0.5174] [0 0 ]
[0.4221 0.3325][0.2850 0.6280] [0.9503 0.5174] 

To do this I tried using

toeplitz(c,r)

where c corresponds to the first column and r to the first row. But I got the following error 'Inputs must be numeric'.

[Star Strider]

It appears to be a ‘cell-of-cells’, so —

cell_matrix = { {[0.9503 0.5174]}
                {[0.2850 0.6280]}
                {[0.4221 0.3325]} }

cell_matrix = 3×1 cell array
    {1×1 cell}
    {1×1 cell}
    {1×1 cell}

M = cellfun(@cell2mat, cell_matrix, 'Unif',0)

M = 3×1 cell array
    {[0.9503 0.5174]}
    {[0.2850 0.6280]}
    {[0.4221 0.3325]}

M = cell2mat(M)

M = 3×2

0.9503 0.5174 0.2850 0.6280 0.4221 0.3325

c = M(:,1)

c = 3×1

0.9503 0.2850 0.4221

r = M(1,:)

r = 1×2

0.9503 0.5174

Tm = toeplitz(c, r)

Tm = 3×2

0.9503 0.5174 0.2850 0.9503 0.4221 0.2850

That would appear to be the desired result.

.