I need to create a vector from a symbolic polynomial function,but when i use sym2poly command, matlab tells me it is not a polynomial, how should i do?

1 vue (au cours des 30 derniers jours)
f1=(497*c1^2 + 497*c2^2 + 497*c3^2 + 11*(c3 + c1*c2)*(c2 - c1*c3)*(c1^2 + c2^2 + c3^2 + 1) + 497)^2/(103684*(c1^2 + c2^2 + c3^2 + 1)^2) + (136*c1^2 + 136*c2^2 + 136*c3^2 + (11*(c2 - c1*c3)*(c1^2 - c2^2 - c3^2 + 1)*(c1^2 + c2^2 + c3^2 + 1))/2 + 136)^2/(103684*(c1^2 + c2^2 + c3^2 + 1)^2) - 1;
sym2poly(f1)
Error using sym/sym2poly (line 30)
Not a polynomial
why matlab tells me this?

Réponse acceptée

Star Strider
Star Strider le 16 Déc 2021
One option is to use the coeffs function —
syms c1 c2 c3
sympref('AbbreviateOutput',false);
f1=(497*c1^2 + 497*c2^2 + 497*c3^2 + 11*(c3 + c1*c2)*(c2 - c1*c3)*(c1^2 + c2^2 + c3^2 + 1) + 497)^2/(103684*(c1^2 + c2^2 + c3^2 + 1)^2) + (136*c1^2 + 136*c2^2 + 136*c3^2 + (11*(c2 - c1*c3)*(c1^2 - c2^2 - c3^2 + 1)*(c1^2 + c2^2 + c3^2 + 1))/2 + 136)^2/(103684*(c1^2 + c2^2 + c3^2 + 1)^2) - 1
f1 = 
f1 = simplify(f1, 500)
f1 = 
[f1n, f1d] = numden(f1)
f1n = 
f1d = 
414736
[f1n_cfs, f1n_trms] = coeffs(f1n) % Numerator Coefficients & Terms
f1n_cfs = 
f1n_trms = 
[f1n_cfs_all, trms_all] = coeffs(f1, 'All')
f1n_cfs_all(:,:,1) = 
f1n_cfs_all(:,:,2) = 
f1n_cfs_all(:,:,3) = 
f1n_cfs_all(:,:,4) = 
f1n_cfs_all(:,:,5) = 
f1n_cfs_all(:,:,6) = 
f1n_cfs_all(:,:,7) = 
trms_all(:,:,1) = 
trms_all(:,:,2) = 
trms_all(:,:,3) = 
trms_all(:,:,4) = 
trms_all(:,:,5) = 
trms_all(:,:,6) = 
trms_all(:,:,7) = 
That is as completely and thoroughly as it is possible to decompose this polynomial expression.
.
  2 commentaires
sebastiano della gatta
sebastiano della gatta le 17 Déc 2021
thank you for the answer but I don't want to completely decompose the polynomial, I just need the vector of this function because then I have to apply the grobner bases to arrive at my solution.
Star Strider
Star Strider le 17 Déc 2021
As always, my pleasure!
The first coeffs call then:
[f1n_cfs, f1n_trms] = coeffs(f1n)
is likely as close as it is possible to get. MATLAB inteprets ‘polynomial’ as a univariate polynomial, the reason the sym2poly call fails.
.

Connectez-vous pour commenter.

Plus de réponses (1)

sebastiano della gatta
sebastiano della gatta le 17 Déc 2021
thank you. I have the last question. Can i compute groebner basis from f1? (The first function that I put in the first question).
  3 commentaires

Connectez-vous pour commenter.

Catégories

En savoir plus sur Polynomials dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by