Effacer les filtres
Effacer les filtres

Confronting column values of two rows in a table?

4 vues (au cours des 30 derniers jours)
Fabio
Fabio le 20 Déc 2021
Commenté : Fabio le 20 Déc 2021
Hello everyone,
I have a table (see attached file) showing specific data (variables as columns) for every element name (rows). I would like to implement a code that allows me to compare between two elements (rows) their respective variable value.
For example, for the giving table, I would like that the code compares the “GWP” variable between element “T” (GWP_T=500) and element “P1” (GWP_P1=400) and it gives me the element name that has a higher “GWP” between the two à “T” (GWP_T=500).
How can I do that?

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Voss
Voss le 20 Déc 2021
t = load('Table.mat');
t = t.Comp;
names = {'T' 'P1'};
[~,idx] = max(t.GWP(ismember(t.Name,names)));
max_name = names{idx}
max_name = 'T'
  3 commentaires
Voss
Voss le 20 Déc 2021
A for loop would work, yes. You would just perform the operation specified in my answer for each pair of variable names, i.e., the names variable up there would get each pair of names and the rest would be the same.
t = load('Table.mat');
t = t.Comp;
all_names = {'T' 'P1'; 'T' 'S2'; 'T' 'P2'; 'T' 'S3' }; % I made a slight modification: to use a 4-by-2 cell array here rather than a 1-by-8 but you can do it with a 1-by-8 if you need to
N = size(all_names,1);
max_names = cell(N,1);
for i = 1:N
names = all_names(i,:);
[~,idx] = max(t.GWP(ismember(t.Name,names)));
max_names{i} = names{idx};
end
display(max_names);
max_names = 4×1 cell array
{'T'} {'T'} {'T'} {'T'}
Fabio
Fabio le 20 Déc 2021
Ok perfect. Thanks a lot

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