How to create a function handle to an object's method?

11 vues (au cours des 30 derniers jours)
D D
D D le 24 Déc 2021
Commenté : D D le 2 Jan 2022
Hi, everyone.
I wanna create a function handle to an object's method. I have two classes, my_class1 and my_class2. my_class2 has a instance of my_class1 as its property. What I want to do is to create function handles to the instance of my_class1, and to use them in my_class2's method. Here's my code and when I tried to run it, it says "Unrecognized function obj.instance_of_my_class1.foo1". What is the correct way? I know eval() can do that, but it's evil isnt it?
classdef my_class1
methods
function foo1(obj, arg1, arg2)
% do something
end
function foon(obj, arg1, arg2)
% do something
end
function obj = my_class1(arg1, arg2)
% do something
end
end
end
classdef my_class2
properties
instance_of_my_class1
func_handles
end
methods
function obj = my_class2()
obj.instance_of_my_class1 = my_class1(1, 2)';
f_names = methods(obj.instance_of_my_class1); % names of my_class1's public methods
obj.func_handles = containers.Map(); % function name -> handle mapping
for f_name = f_names
handle = str2func(strcat('obj.instance_of_my_class1.', f_name{1, 1})); % HOW?
obj.func_handles(f_name) = handle;
end
end
function foo(obj, function_name)
% for example
f = obj.func_handles(function_name);
f(); % Unrecoginsed function
end
end
end

Réponse acceptée

Matt J
Matt J le 24 Déc 2021
tmp=obj.instance_of_my_class1;
for f_name = f_names
obj.func_handles(f_name) = @(varargin)tmp.(f_name)(varargin{:});
end
  4 commentaires
Matt J
Matt J le 1 Jan 2022
Should that matter?
D D
D D le 2 Jan 2022
Doesn't matter. Made a mistake.

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