how to convert array of cells within array of cells in single cell array

A= {<1x1 cell> <1x3 cell> [4,0] <1x4 cell>}

where

<1x1>= [2,3,4]

<1x3>= [ ] [3,4] [3,8,13]

<1x4>= [9,4] [9,8,13] [ ] [9,14,19]

so i want my answer to be in form of a single array of cells as below,

B={ [2,3,4] [3,4] [3,8,13] [4] [9,4] [9,8,13] [9,14,19] }

[Image Analyst]

OK I see that you want null cells to be left out, but how did cell number 4 come to contain [4]:

B={ [2,3,4] [3,4] [3,8,13] [4] [9,4] [9,8,13] [9,14,19] }

The third cell of A contains a vector [4, 0]. But B{4} is [4]. What happened to the 0? Do you want to exclude zeros also for some reason?

Answer 1

[Stephen23]

A = {{[2,3,4]},{ [],[3,4],[3,8,13]},{[4,0]},{[9,4],[9,8,13],[],[9,14,19]}}

A = 1×4 cell array
    {1×1 cell}    {1×3 cell}    {1×1 cell}    {1×4 cell}

B = [A{:}]

B = 1×9 cell array
    {[2 3 4]}    {0×0 double}    {[3 4]}    {[3 8 13]}    {[4 0]}    {[9 4]}    {[9 8 13]}    {0×0 double}    {[9 14 19]}

https://www.mathworks.com/help/matlab/matlab_prog/comma-separated-lists.html

https://www.mathworks.com/matlabcentral/answers/320713-how-to-operate-on-comma-separated-lists

[Mausmi Verma]

Thank u for ur promt reply......but i think i missed something while asking the question as,

A= {<1x1 cell> <1x3 cell> [4,0] <1x4 cell>}

where

<1x1> {2,3,4}

<1x3>= { [ ] } { [3,4] } { [3,8,13] }

<1x4>= { [9,4] } { [9,8,13] } { [ ] } { [9,14,19] }

there is nested cell array within cell array so i want my answer to be in single cell array,

as below,

B={ [2,3,4] [3,4] [3,8,13] [4] [9,4] [9,8,13] [9,14,19] }

please help

[Voss]

@Stephen's answer creates a single cell array, as requested. The only difference is between his result and the result you want is that his result retains the empty elements from the original cell array. You can remove the empty elements like this:

B(cellfun(@(x)isempty(x),B)) = [];

[Stephen23]

Or without the anonymous function:

B(cellfun(@isempty,B)) = [];

"...so i want my answer to be in single cell array"

and is what my answer gives you.