PCOLOR command in Matlab App Designer

I have achieved working and running code in Matlab, but I have problem converting it for use in the App Designer. I am mostly struggling with the syntax. For the graph I am using UIAxes in app designer.

the code:

E=[1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;1 1 0 0 1 0;]
grid=pcolor(padarray(E,[1 1],'replicate','post'))
grid.EdgeColor=[0 0 0]
grid.LineWidth=3
colormap(jet(4))
set(gca,'ydir','reverse')
axis equal

Thank you very much for your help

Michal Cerny

Answer 1

[Walter Roberson]

Instead of passing the uiaxes as the first parameter, use the 'Parent' name/value pair.

grid = pcolor(padarray(E,[1 1],'replicate','post'), ...
    'Parent', app.UIAxes, 'EdgeColor', [0 0 0], 'LineWidth', 3);
colormap(app.UIAxes, jet(4))
app.UIAxes.YDir = 'reverse';
axis(app.UIAxes, 'equal')

[Michal Cerny]

Error using pcolor (line 50)

Too many input arguments.

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Thank you for help. For some reason it still gives the error above. There is no other "pcolor" command used anywhere in the code.

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[Image Analyst]

Try this:

E = rand(5,5); % Just for demo - you should delete this line.
app.UIAxes = axes(); % Just for demo - you should delete this line.
paddedE = padarray(E,[1 1],'replicate','post')

paddedE = 6×6

0.1886 0.4694 0.1405 0.3392 0.2175 0.2175 0.8035 0.1835 0.3030 0.5094 0.1928 0.1928 0.6563 0.1289 0.4795 0.6464 0.4215 0.4215 0.6175 0.4941 0.3259 0.2673 0.0400 0.0400 0.2382 0.3621 0.1431 0.6461 0.7562 0.7562 0.2382 0.3621 0.1431 0.6461 0.7562 0.7562

hp = pcolor(paddedE, 'Parent', app.UIAxes);
hp.EdgeColor = [0 0 0];
hp.LineWidth = 3;
colormap(app.UIAxes, jet(4))
app.UIAxes.YDir = 'reverse';
axis(app.UIAxes, 'equal')