LDL does not support complex symmetric matrices
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Nathan Zhao
le 6 Jan 2022
Commenté : EMCanuck1
le 18 Fév 2025
Given that you cannot factorize a complex symmetric matrix with LDL in MatLab, I was wondering if there was a particular reason? Is there some package which can perform this factorization?
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Christine Tobler
le 7 Jan 2022
Largely the reason LDL doesn't support this is that it's less commonly requested for complex symmetric matrices than for complex Hermitian ones, so LDL only supports the more common variant. We would also need some option to indicate which of the two modes is meant to be used.
There is a LAPACK function ZSYTRF that you can call from a mex-file to get the complex symmetric LDL decomposition.
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Christine Tobler
le 10 Jan 2022
Yes, LDL for sparse matrices doesn't support complex at all, neither the Hermitian nor the complex symmetric case. This is again not based on mathematics, just on practical considerations of resources and commonality of the use case.
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David Goodmanson
le 6 Jan 2022
Modifié(e) : David Goodmanson
le 7 Jan 2022
Hi Nathan,
the LDL decomposition works for hermitian matrices. In LDL the D matrix is hermitian, so
if A = L*D*L', then A' = L*D' *L' = L*D*L' = A, and A has to be hermitian.
But a symmetric complex matrix is not hermitian, so LDL won't work.
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Yaroslav Urzhumov
le 19 Jan 2023
David,
LDL for a symmetric matrix implies A=L*D*L.', where .' is the usual (rather than complex conjugate) transpose. You can easily see that this decomposition is a symmetric matrix - even if D is complex-valued. It's a different kind of decomposition.
EMCanuck1
le 18 Fév 2025
I agree with Yaroslav. My work involves decomposing a symmetric complex matrix and A=L*D*L.' is valid. The fact that ldl() threw an error made me second-guess my derivation, but it is correct. What should the LDL be called for complex symmetric matrices, I wonder?
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