Plotting a year by hour

I'm attempting to plot a year by date and hour. Someone suggested the following code:

 D = datevec(datenum(1992,1,1:1/24:366));

which produces a years worth of data plus one hour, so I've got 01-01-1992, 0:00:00 to 31-12-1992 0:00:00. So I've got 8761 rows of data for my hours, but only 8760 rows of input data. If anyone can point me in the right direction that would be great. Thank you.

Answer 1

[Matt Fig]

Also, you realize 1992 was a leap year? Is that the year your data was taken? If it is for a generic year, why not use:

D2 = datevec(datenum(1993,1,1:1/24:365+23/24));  % makes 8760 rows

[Claire]

Thank you, that's great, much appreciated.

Answer 2

[Matt Tearle]

So the issue is how to extract the first 8760 elements of a vector of 8761 points? That's easy enough:

plot(x(1:end-1),y)

Answer 3

[Matt Tearle]

If you're starting just with data and the knowledge that it was recorded hourly throughout a given year, why not just do something like:

t = datenum(yr,1,1) + (0:(length(x)-1))/24;
D = datevec(t);

Or, alternatively

tstart = datenum(yr,1,1);
tend = datenum(yr+1,1,1) - 1/24;
n = 24*(tend-tstart) + 1;
if n==length(x)
   t = linspace(tstart,tend,n);
   % etc
else
   error('wrong number of data points')
end