How to speed up this code?

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K E
K E on 13 Nov 2014
Commented: K E on 14 Nov 2014
I would like fast code to find the index of the closest element of a vector to a scalar. Here's what I am doing now,
someVector = [1 3.5 5 7 9];
someScalar = 4;
iClosest = find(abs(someVector - someScalar) == min(abs(someVector - someScalar)));
The returned index is 2 since the 2nd element is closest to 4. A parent program spends a lot of time on this line according to the profiler. I'd like to know if it can be done faster or if there's a built-in solution.

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 13 Nov 2014
[~,idx]=min(abs(someVector - someScalar))
  1 Comment
K E
K E on 14 Nov 2014
Thanks, knew there was a more elegant way.

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