Matlab recommends to replace histc by histcounts. However, I obtain different results:
x=[123.1900 120.9395 120.9395 120.9395 112.6711 415.4625];
y=[112.6711 120.9395 123.1900 415.4625]
which yields
K>> histc(xRd(:),auxVecX)
ans =
1
3
1
1
but
histcounts(xRd(:),auxVecX)
ans =
1 3 2
How can I handle histcounts so that the outputs are the same?

1 commentaire

Gunther Schaaf
Gunther Schaaf le 12 Jan 2022
Sorry, I meant histc(x,y) versus histcounts(x,y).

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 Réponse acceptée

Bruno Luong
Bruno Luong le 12 Jan 2022

1 vote

The result differ by the way the last bin is handed in both function. To get the same result you must change the last edge to Inf for histc
x=[123.1900 120.9395 120.9395 120.9395 112.6711 415.4625];
y=[112.6711 120.9395 123.1900 415.4625];
xRd = x;
auxVecX = y;
auxVecX(end) = Inf
auxVecX = 1×4
112.6711 120.9395 123.1900 Inf
histc(xRd(:),auxVecX)
ans = 4×1
1 3 2 0

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