Help with for loop and if else statement
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I am writing to code for the attached capture 1 image, and it is supposed to obtain the graph as shown in the capture 2 image.
I used for and if-else statement to write the code, however it is not working. If possible can anyone look into it? Thanks in advance.
y=0:1000;
for i=0:length(y)
if y(i) <= 10
Q1=1;
elseif (y(i) > 10) && (y(i)<100)
Q2=0.32*y-2.2;
else y(i) > 100
Q3 =300/sqrt(y);
end
Q=(Q1+Q2+Q3)
end
semilogx(y,Q)
0 commentaires
Réponses (3)
Image Analyst
le 13 Jan 2022
Modifié(e) : Image Analyst
le 13 Jan 2022
You need to index L and Q:
L = linspace(0, 200, 2000);
Q = ones(1, length(L)); % Initialize to 1
for k = 2 : length(L)
if L(k) <= 10
Q(k) = 1;
elseif (L(k) > 10) && (L(k)<= 100)
Q(k)=0.32 * L(k) - 2.2;
elseif L(k) > 100
Q(k) =300/sqrt(L(k));
end
% Q=(Q1+Q2+Q3)
end
loglog(L, Q, 'LineWidth', 3);
grid on;
xlabel('L', 'FontSize', 20)
ylabel('Q', 'FontSize', 20)
Of course you don't need a loop - you can do it vectorized if you want but it's your homework so I didn't try to modify it too much.
Mathieu NOE
le 13 Jan 2022
hello
here you are .
Q andy must be indexed in the loop (Q(k) , y(k))
only one Q variable suffice for all cases - no need to create multiple Q's
also please don't use i or j for loop index as your are shadowing their native role (i = j = sqrt(-1) for complex numbers)
clc
clearvars
y=1:1000;
for k=1:length(y)
if y(k) <= 10
Q(k)=1;
elseif (y(k) > 10) && (y(k)<100)
Q(k)=0.32*y(k)-2.2;
else y(k) > 100
Q(k) =300/sqrt(y(k));
end
end
loglog(y,Q)
0 commentaires
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!