Effacer les filtres
Effacer les filtres

countdown the received character

1 vue (au cours des 30 derniers jours)
jarvan
jarvan le 17 Nov 2014
Commenté : Star Strider le 18 Nov 2014
Hi guys, I have a function which will accept the characters and n, this function is a cell array with strings of decreasing lengths, from the integer n to 1. For example, when I type buildstr('a',4), the answer should be 'abcd' 'abc' 'ab' 'a'. However the code below doesnt satisfy my requirement. Can someone point out the error code?
function str=buildstr(ch,n)
temp='';
if(n<0)
str='';
else
str=cell(n,1);
for i=n:1
if(i==1)
str(i)={char(ch)};
else
temp=char(str(i+1));
str(i)={strcat(temp,char(ch))};
end
end
end

Réponse acceptée

Star Strider
Star Strider le 17 Nov 2014
You’re almost there.
if(n<0)
str='';
else
str=cell(n,1);
for i=n:-1:1
if(i==n)
str{i}=char(ch);
else
temp=char(str{i+1}+1);
str{i}=strcat(char(ch),temp);
end
end
end
There were three problems:
  1. Your loop wasn’t iterating because in MATLAB, for loops by default count upward, so if the terminal value is less than the initial value, the loop is satisfied and never iterates. You need to decrement it by telling it to count down, specifying the interval to (in this instance) to be -1;
  2. Your ‘temp’ variable subscript needs to ‘look back’ (which is to say to add 1 to ‘i’) at every iteration, and add 1 to the previous value of ‘str’;
  3. Your strcat arguments were reversed.
A minor observation: it’s best to not use ‘i’ or ‘j’ as loop counters. They are the imaginary operators in MATLAB.
  2 commentaires
jarvan
jarvan le 18 Nov 2014
i=n:-1:1 is all I need in the code, I was frustrating in counting down with for-loop. thanks for sharing your information
Star Strider
Star Strider le 18 Nov 2014
My pleasure!

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