Finding x for y = f(x) in simulink
8 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have an equation which is uel = 3 + 3 * iel + 3 * log (3 * iel +1) a.k.a uel = f(iel) and I want to find iel ( uel is already known), so I have used fsolve to solve the problem in matlab and it works. Here is the code
---------------------------------------------------------------------
function iel = test(uel)
f = @(x) uel-(3 + 3 * x + 5 * log(3 * x + 1));
iel = fsolve(f,uel);
end
----------------------------------------------------------------------
But when i try to add this code into matlab function block in simulink, the model just don't run. I want my input to be uel and output to be iel. Can anyone please help me on this problem. Thank you so so much
2 commentaires
Réponses (2)
Paul
le 19 Jan 2022
Modifié(e) : Paul
le 19 Jan 2022
According to the Symbolic Math Toolbox, the solution can be expressed as
%iel = wrightOmega(uel/3 - log(3) - 2/3) - 1/3
assuming that iel and uel are real. If they can be complex, the expression for iel is the same, but there are some other conditions that have to be satisfied.
Check
%doc wrightOmega
for more info.
Check a couple of test cases (note that I changed the 5 to a 3 in the function test() to match the equation in the question)
uel = 0.3
iel = test(uel)
iel = wrightOmega(uel/3 - log(3) - 2/3) - 1/3
uel = 5.4
iel = test(uel)
iel = wrightOmega(uel/3 - log(3) - 2/3) - 1/3
function iel = test(uel)
% f = @(x) uel-(3 + 3 * x + 5 * log(3 * x + 1)); % doesn't match equation in Question
f = @(x) uel-(3 + 3 * x + 3 * log(3 * x + 1));
iel = fsolve(f,uel);
end
0 commentaires
Dat Trương Lê Trí
le 6 Juil 2022
Hi, I am facing the same problem, did you have any posible solution for this case?
0 commentaires
Voir également
Catégories
En savoir plus sur Spectral Measurements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!