Is this possible to convert a thick line or curve into its thinner version
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Is this possible to convert a thick line or curve into its thinner version in an image using Matlab / Octave? Please view the image. Right side curves (alphabets) are thicker and need to be converted into the left ones. i.e., a single line version is needed.
thanks

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Ahmet Cecen
le 18 Nov 2014
Take an image with the best exposure possible, having high contrast between the paper white and font black. Use a simple tresholding method like Otsu's and get a BW binary image. Use:
a) erosion (imerode) with a disk structural element (strel)
or
b) use bwulterode
or
c) you can also use bwmorph with 'skel' option.
I am sure there are other ways to do it too. Just a couple simple ones that might help start.
3 commentaires
Ahmet Cecen
le 20 Nov 2014
What's happening there is you are eroding on the white instead of black. You need to invert the image using:
BW=1-BW;
so that the pixels where the letters are have 1's on them (which means your image should have white letters and black background). Now try them again. I think Image Analyst is right the first 2 options would only work in very specific conditions, but give them a try anyways its good learning experience.
Image Analyst
le 20 Nov 2014
Then why did you accept it. If you had used my answer, it would have worked.
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Image Analyst
le 18 Nov 2014
You can skeletonize it after thresholding.
binaryImage = grayImage < 128; % or whatever.
skeletonImage = bwmorph(binaryImage, 'skel', inf);
You cannot use imerode() because it will break apart your object into multiple objects. You cannot use bwulterode because it will shrink the blob down to a single point.
2 commentaires
Image Analyst
le 20 Nov 2014
Modifié(e) : Image Analyst
le 20 Nov 2014
It did not work because you did not do what I recommended . Look at the line where I thresholded. It will take everything that is darker than 128 and turn it white. Why did you not do that? You should notice that I even specifically said NOT to use bwulterode() or imerode(). All I can figure is that this reply was really meant for Ahmet, not for me. I know you accepted his answer already, but if you need any more help, feel free to ask.
baby
le 24 Nov 2014
1 commentaire
Image Analyst
le 24 Nov 2014
Again, this is not my code. You took the skeleton of a2, which is not the binary image. The binary image is the badly-named "a". So you're still not doing what I suggested - perhaps the poor variable names confused you, that's why I recommend using descriptive variable names like grayImage, binaryImage, skeletonImage, etc. Please attach your original B image that you used so I can try it.
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