Why am i getting two different MSE, while using formula and syntax immse?

IS there any mistake in the formula applied for mean squarred error?

moving_img= imread("AT3_1m4_02.tif");
fixed_img=  imread("AT3_1m4_03.tif");

crp_mv_img=imcrop(moving_img, [235, 210, 100, 100]);
crp_fx_img=imcrop(fixed_img, [235, 210, 100, 100]);

mse_1=immse(crp_fx_img,crp_mv_img)

mse_1 = 979.2353

[r,c]=size(crp_fx_img);
mse_2= sum((crp_mv_img-crp_fx_img).^2,"all")/(r*c)

mse_2 = 44.0342

Is mse_2 wrong?

Answer 1

[DGM]

The reason is that the two images are integer-class. The difference and square may result in data truncation.

moving_img = imread("AT3_1m4_02.tif");
fixed_img = imread("AT3_1m4_03.tif");

crp_mv_img = imcrop(moving_img, [235, 210, 100, 100]);
crp_fx_img = imcrop(fixed_img, [235, 210, 100, 100]);

mse_1 = immse(crp_fx_img,crp_mv_img)

mse_1 = 979.2353

[r,c] = size(crp_fx_img);
se = (double(crp_mv_img)-double(crp_fx_img)).^2; % square error
[min(se(:)) max(se(:))] % values are outside of range for uint8

ans = 1×2

0 27225

mse_2 = sum(se,"all")/(r*c)

mse_2 = 979.2353

[Samson David Puthenpeedika]

Oh understood! Thankyou so much for the explanation.