how could i turn this into a 5 by 5 filter

4 vues (au cours des 30 derniers jours)
Lewis Laurence
Lewis Laurence le 23 Jan 2022
Commenté : Lewis Laurence le 23 Jan 2022
I= imread('peppers.png');
I2=I;
[r, c,]=size(I);
for i = 2:r-1
for j = 2: c-1
uint8=[I(i-1,j-1),I(i-1,j),I(i-1,j+1),I(i,j-1),I(i,j),I(i,j+1),...
I(i+1,j-1),I(i+1,j),I(i+1,j+1)];
uint8=sort(uint8);
I2(i,j)= uint8(5);
end
end
figure;
imshow(I);
title('peppers noisy');
figure;
imshow(I2);
title('peppers');
  2 commentaires
DGM
DGM le 23 Jan 2022
Modifié(e) : DGM le 23 Jan 2022
The last comment I left on your other question implements a 5x5 median filter. The filter size is adjustable.
I also included a link to a second example of an adjustable (example shows 5x5) size median filter using a slightly different approach.
Note that in this version of your code, you're shadowing the built-in function uint8() by using that as a variable name.
Lewis Laurence
Lewis Laurence le 23 Jan 2022
thank you for your comments. Im just struggling on how I would implement this.

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Réponses (1)

Matt J
Matt J le 23 Jan 2022
Modifié(e) : Matt J le 23 Jan 2022
I2=medfilt2(I,[5,5]);

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