How to split binary cells and convert them to dec?

I have a cell array consisting of binary 100x1 e.g

{'0100101000101000'}

{'0100101000101000'}

{'0100101000101000'}

...

{'0100101000101000'}

How do i take the first 3 binary from each cell and then convert it into dec?

maybe a cellfun can be helpful here but i do get some errors

I know you can use bin2dec i should expect a 2 for every cell.

Thanks!

Answer 1

[zhehao.nkd]

C{1} = {'0100101000101000'};
C{2} = {'0100101000101000'};
C{3} = {'0100101000101000'};

if C is your original cell, then:

cellfun(@(x) bin2dec(x{1}(1:3)),C)

ans = 1×3

2 2 2

Is that what you need?

[MKM]

Perfect, I actually managed to do this myself eventually. My version of it is:

binarystrip = cellfun(@(x) x(1:3), C, 'uniformoutput',false)
x = bin2dec(binarystrip)

Thanks for the input too.

Answer 2

[Stephen23]

More efficient than using CELLFUN:

C = {'0100101000101000';'0100101000101000';'0100101000101000';'0100101000101000'}

C = 4×1 cell array
    {'0100101000101000'}
    {'0100101000101000'}
    {'0100101000101000'}
    {'0100101000101000'}

V = [4,2,1]*sscanf(sprintf('%s ',C{:}),'%1d%1d%1d%*d',[3,Inf])

V = 1×4

2 2 2 2