How to generate horizontal titles on the table generated by array2table

4 vues (au cours des 30 derniers jours)
Aarav Shah
Aarav Shah le 26 Jan 2022
tableGen =
1.0000 0 0.5000 0.7500 0.8750 0.8125 0.8438 0.8594 0.8516 0.8477 0.8457 0.8447
2.0000 1.0000 0.5000 0.2500 0.1250 0.0625 0.0312 0.0156 0.0078 0.0039 0.0020 0.0010
1.0000 2.0000 3.0000 4.0000 5.0000 6.0000 7.0000 8.0000 9.0000 10.0000 11.0000 12.0000
table =
3×12 table
tableGen1 tableGen2 tableGen3 tableGen4 tableGen5 tableGen6 tableGen7 tableGen8 tableGen9 tableGen10 tableGen11 tableGen12
_________ _________ _________ _________ _________ _________ _________ _________ _________ __________ __________ __________
1 0 0.5 0.75 0.875 0.8125 0.84375 0.85938 0.85156 0.84766 0.8457 0.84473
2 1 0.5 0.25 0.125 0.0625 0.03125 0.015625 0.0078125 0.0039062 0.0019531 0.00097656
1 2 3 4 5 6 7 8 9 10 11 12
Is there a way to position the titles on the left handed side, as if they were part of the existing matrix? That is to say, the left hand side instead of top? Thanks.

Réponses (1)

Arif Hoq
Arif Hoq le 26 Jan 2022
You can try with this:
tableGen=[1.0000 0 0.5000 0.7500 0.8750 0.8125 0.8438 0.8594 0.8516 0.8477 0.8457 0.8447
2.0000 1.0000 0.5000 0.2500 0.1250 0.0625 0.0312 0.0156 0.0078 0.0039 0.0020 0.0010
1.0000 2.0000 3.0000 4.0000 5.0000 6.0000 7.0000 8.0000 9.0000 10.0000 11.0000 12.0000
];
inv=tableGen';
LastName={'tableGen1','tableGen2','tableGen3','tableGen4','tableGen5',...
'tableGen6','tableGen7','tableGen8','tableGen9','tableGen10','tableGen11','tableGen12'};
find_table=array2table(inv,'RowNames',LastName);

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