How to access the 3rd element in a for loop?

3 vues (au cours des 30 derniers jours)
Steven Gangano
Steven Gangano le 31 Jan 2022
Commenté : Steven Gangano le 31 Jan 2022
investment = 1000;
interestRate = 0.01;
months =[1:12];
for month = months
investment = investment * (1 + interestRate);
end
Displays:
investment = 1010
investment = 1020.1
investment = 1030.3
investment = 1040.6
investment = 1051.0
investment = 1061.5
investment = 1072.1
investment = 1082.9
investment = 1093.7
investment = 1104.6
investment = 1115.7
investment = 1126.8

Réponse acceptée

Walter Roberson
Walter Roberson le 31 Jan 2022
You would have to evalc() an invocation of the for loop, and do text processing on the output.
We would recommend that you instead record the values as you go.
investment = 1000;
interestRate = 0.01;
months =[1:12];
for month = months
investment(month+1,1) = investment(month,1) * (1 + interestRate);
end
format long g
investment
investment = 13×1
1.0e+00 * 1000 1010 1020.1 1030.301 1040.60401 1051.0100501 1061.520150601 1072.13535210701 1082.85670562808 1093.68527268436
The third output of the loop would then be investment(4) [because investment(1) is the initial value]
  1 commentaire
Steven Gangano
Steven Gangano le 31 Jan 2022
Thank you! Can you explain the part:
investment(month+1,1)
What does month+1 do?

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Plus de réponses (1)

KSSV
KSSV le 31 Jan 2022
investment = zeros(13,1);
investment(1) = 1000;
interestRate = 0.01;
months =[1:12];
for month = months
investment(month+1) = investment(month) * (1 + interestRate);
end
investment(4)
ans = 1.0303e+03

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