extracting files having names with the same date from a dataset

I am having some txt files as a training dataset for a modele I'm trying to build.

if we asumed that the txt files names has the format YYYYMMDDHHmm as 196611110428.

if I would like to extract files that have the month=12, day=05, hour=22. discarding the years and the minutes, How I can possibly do that?

Answer 1

[Stephen23]

Here is one approach, tested on the attached files:

P = '.'; % absolute or relative path to where the files are saved
S = dir(fullfile(P,'*.txt'));
[~,F,~] = fileparts({S.name});
T = datetime(F,'InputFormat','uuuuMMddHHmm');
X = T.Month==12 & T.Day==5 & T.Hour==22

X = 1×6 logical array
   0   1   1   0   0   1

{S(X).name} % training set

ans = 1×3 cell array
    {'196612052228.txt'}    {'196612052258.txt'}    {'202212052228.txt'}

{S(~X).name} % not training set

ans = 1×3 cell array
    {'196611110428.txt'}    {'196612110428.txt'}    {'202211110428.txt'}

Answer 2

[Walter Roberson]

dinfo = dir('*120522.txt');
filenames = {dinfo.name};

[Stephen23]

That does not take into account the minutes.

Adding another asterisk will not fix that ... if only DIR supported ? to match one character :(

Answer 3

[Sambit Supriya Dash]

a = 196611110428;
strA = string(a);
d = datetime(strA,'InputFormat','yyyyMMddHHmm');
disp(d)
Month = month(d);
Day = day(d);
Hour = hour(d);