splitting a periodic sweeping matrix

I have a matrix that goes from a negative value to a positive value through 0 and then from a positive value to negative value . This is repeated for 100 times. How do i divide the matrix so that i get all the negative sweeps in one matrix and all the positive sweep in another. For example see the attached file.

Réponses (1)

Matt J
Matt J le 25 Nov 2014
neg=A(A<=0);
pos=A(A>0);

2 commentaires

DebiPrasad
DebiPrasad le 25 Nov 2014
hey Thanks Matt, but i don't need the matrix to be only containing negative and positive values, but sweeps. What i mean is first vector will have values -2 to 2 thats a sweep . another vector will contain the sweep of 2 to -2.
Matt J
Matt J le 25 Nov 2014
Modifié(e) : Matt J le 25 Nov 2014
idx=diff(A)>0;
idx=[idx(1), idx];
pos_sweeps=A(idx);
neg_sweeps=A(~idx);

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le 25 Nov 2014

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