How can I create a function of my code

Hi, I got a code that I want to convert to a a function so I do not write for each variable the whole code. I do not really understand the documentation page because I have a code that is quite big and I get confused. My code is to generate the same variable without the doubles inside. The output that I want is the same name as the variable input. So that is where I got the problem. I post the code so you can see:

function y = removedbl(var)

numCells = numel(Time_msg_match); %Time_msg_match was the original variable for this code was created
Time_msg_match2 = zeros(numCells+10000, 1);
vector2Index = 1;
for k = 1 : numCells
    len = length(Time_msg_match{k});
    if len == 1
        Time_msg_match2(vector2Index) = Time_msg_match{k}; 
        vector2Index = vector2Index + 1;
    else
        fprintf('Row %d has %d elements in it.\n', k, length(Time_msg_match{k}));
        for k2 = 1 : len
            thisVector = Time_msg_match{k};
            Time_msg_match2(vector2Index) = thisVector(k2);
           
            vector2Index = vector2Index + 1;
        end
    end
end

if vector2Index < numCells
    Time_msg_match2 = Time_msg_match2(1 : vector2Index - 1);
    
end
% fprintf('Original   Time_msg_match had %d rows.\n', numCells) %Nos dice de que numero a que numero pasamos al quitar las celdas vacias
% fprintf('Afterwards Time_msg_match had %d rows.\n', numel(Time_msg_match2))

end

Answer 1

[DGM]

This probably covers what you are trying to do. I assume your problem description is as follows:

1. You have a cell array of scalars and row vectors.
2. Read the cells in column-major order
3. Reshape the cell contents to a column vector
4. Concatenate to form one large column vector

aaa = {1,2,3,4,5,ones(1,5),2*ones(1,5),3*ones(1,5)};

bbb = removedbl(aaa)

Row 6 has 5 elements in it.
Row 7 has 5 elements in it.
Row 8 has 5 elements in it.

bbb = 20×1

1 2 3 4 5 1 1 1 1 1

ccc = vectorizecell(aaa)

ccc = 20×1

1 2 3 4 5 1 1 1 1 1

% this is your function with some fixes
function Time_msg_match2 = removedbl(Time_msg_match)
    numCells = numel(Time_msg_match); %Time_msg_match was the original variable for this code was created
    Time_msg_match2 = zeros(numCells+10000, 1); 
    vector2Index = 1;
    for k = 1 : numCells
        len = length(Time_msg_match{k});
        if len == 1
            Time_msg_match2(vector2Index) = Time_msg_match{k}; 
            vector2Index = vector2Index + 1;
        else
            fprintf('Row %d has %d elements in it.\n', k, length(Time_msg_match{k}));
            for k2 = 1 : len
                thisVector = Time_msg_match{k};
                Time_msg_match2(vector2Index) = thisVector(k2);
                
                vector2Index = vector2Index + 1;
            end
        end
    end
    
    if vector2Index < numCells+10000 % to fix padding
        Time_msg_match2 = Time_msg_match2(1 : vector2Index - 1);
        
    end
end

% this is an alternative method to do the same
function outvec = vectorizecell(inarray)
    isrv = cellfun(@isrow,inarray);
    if ~all(isrv(:))
        error('VECTORIZECELL: some cells do not contain row vectors')
    end
    
    inarray = cellfun(@(x) x(:),inarray,'uniform',false);
    outvec = cell2mat(inarray(:));
end

If the restriction to "row vectors only" does not apply, you can remove the first few lines of vectorizecell(). Matrix contents will be vectorized in column-major order. If you want it to handle these cases in row-major order, then let me know.

[flashpode]

and the name of the variable I use with the function keeps the original name?

[DGM]

I don't understand what you're asking. Fom the perspective of the calling scope, the variable passed to the function is not changed.

[flashpode]

great!! Than you!!