Storing fewer decimal places in an array to display using a uitable
Afficher commentaires plus anciens
I have a list of varaibles that are required to be displayed however, I can't work out how to manipulate the values so that they are presentable when dispalyed in the uitable. I need to decrease the number of decimal places dispalyed and centralise them in the table however I can't work out, nor find on previous and related forums, how to do this.
Thanks yoh in advance for your help.
2 commentaires
Walter Roberson
le 4 Fév 2022
Is this for "traditional figures" (GUIDE) or "uifigure" (App Designer) ? I would need to research for uifigure(); for traditional figures, the method of centering each entry requires converting to a cell array of character vectors, each of which has to have some HTML 1.1 code added to it.
John Bach
le 4 Fév 2022
Réponse acceptée
Simon Chan
le 4 Fév 2022
Change the number to a string by using function sprintf as follows:
uit1 = uitable(uif,'Position',[5 155 500 100]);
uit1.Data = rand(3,5); % Upper uitable using number
uit2 = uitable(uif,'Position',[5 10 500 100]);
uit2.Data = arrayfun(@(x) sprintf('%.2f',x),rand(3,5),'uni',0); % Lower uitable using string
7 commentaires
John Bach
le 4 Fév 2022
Simon Chan
le 4 Fév 2022
You may accept the answer if you find it useful. Thank you.
Walter Roberson
le 4 Fév 2022
This will work fine for using a fixed number of decimal places.
In the special case of exactly 2 decimal places, you could instead have set the column format to 'bank'
Unfortunately, using this method of sprintf() will typically result in the values being left-justified inside the entries, rather than center justified (as requested in the question) or right justified (which would tend to look more natural as it would line up the decimal places.) Also be sure to use a fixed-width font if you are lining up the decimal point.
Simon Chan
le 4 Fév 2022
Thank you for the comment.
Yes, a liitle bit more work for right justified.
uit1 = uitable(uif,'Position',[5 155 500 100]);
uit1.Data = rand(3,5); % Upper uitable using number
uit2 = uitable(uif,'Position',[5 10 500 100]);
uit2.Data = arrayfun(@(x) sprintf('%.2f',x),rand(3,5),'uni',0); % Lower uitable using string
s2 = uistyle('HorizontalAlignment','right');
addStyle(uit2,s2);
Walter Roberson
le 4 Fév 2022
uistyle is for uifigure only and cannot be used for traditional figures
uif = figure(); %traditional figure not uifigure
uit1 = uitable(uif,'Position',[5 155 500 100]);
uit1.Data = rand(3,5) * 100; % Upper uitable using number
uit2 = uitable(uif,'Position',[5 10 500 100]);
uit2.Data = arrayfun(@(x) sprintf('<HTML><CENTER>%.2f</CENTER>',x),uit1.Data,'uni',0); % Lower uitable using string
You might notice that the alignment is not center in practice. And if you use
uit2.Data = arrayfun(@(x) sprintf('<HTML><TBODY><TR><TD ALIGN="RIGHT">%.2f</TD></TR></TBODY>',x),uit1.Data,'uni',0); % Lower uitable using string
then in practice the alignment is not right (or center if you use that.) But you can tell that TBODY was used: a heavier weight of font is used for the characters.
In theory you can use HTML 1.1 in that context; in practice it can be difficult to get to work.
I seem to remember that I did get it to work in some earlier releases. Unfortunately, it would probably be difficult for me to find the appropriate postings now.
John Bach
le 5 Fév 2022
Plus de réponses (0)
Catégories
En savoir plus sur Develop Apps Programmatically dans Centre d'aide et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
