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How to do for function in MATLAB be doing the pseudocode below ?

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Mohammed AlQahtani
Mohammed AlQahtani le 9 Fév 2022
Clôturé : Stephen23 le 9 Fév 2022
  3 commentaires
DGM
DGM le 9 Fév 2022
Normally, you start by working out the parts that you can work out. Then once you discern that you cannot make more progress without consultation, you organize the sum of what you've accomplished so far and formulate a series of pointed questions which you yourself design to give you targeted insight into specific parts of the problem which you don't yet understand.
Then when you approach someone else for consultation, you communicate by demonstration that 1) you've made earnest effort, and 2) you communicate the current scope of your understanding.
Mohammed AlQahtani
Mohammed AlQahtani le 9 Fév 2022
clear
clc
a=1.9;
b=1.8;
N=17;
TOL=10^-5;
i=1;
f=@(x) 2*sin(x);
fa=f(a);
while i<=N
p=a+((b-a)/2);
fp=f(p);
if (fp==0)||((b-a)/2<TOL)
fprintf("Procedure compueted successfully with p=%.9f",p);
return
end
i=i+1;
if fa*fp > 0
a=p;
fa=fp;
else
b=p;
end
end
I couldn't do it by for loop

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