l=633*(10)^(-9);
k0=(2*pi)/l;
nc=1.33;
na=1.43265;
nf=1.59;
nm=0.064+1i*4;
ns=1.49;
a=54:0.01:70
df=1:1:300;
nf=1.59;
k0=(2*pi/633);
Nm=nf*sind(a);
Snc=zeros(length(a),length(df));
Sna=zeros(length(a),length(df));
Sda=zeros(length(a),length(df));
p=1;
ds=((1-p)./(k0.*sqrt(Nm.^2-ns.^2)))+(p./((Nm./nf).^2+(Nm./ns).^2-1).*(k0.*sqrt(Nm.^2-ns.^2)));
dc=((1-p)./(k0.*sqrt(Nm.^2-nc.^2)))+(p./((Nm./nf).^2+(Nm./nc).^2-1).*(k0.*sqrt(Nm.^2-nc.^2)));
da=((1-p)./(k0.*sqrt(Nm.^2-na.^2)))+(p./((Nm./nf).^2+(Nm./na).^2-1).*(k0.*sqrt(Nm.^2-na.^2)));
Snc= ((nc/Nm).*((nf.^2-Nm.^2)./(nf.^2-nc.^2)).*(dc./(ds+df+dc)).*(2.*(Nm.^2./nc.^2)-1));
Sna= ((na./Nm).*((nf.^2-Nm.^2)./(nf.^2-na.^2)).*(da./(ds+df+da)).*(2.*(Nm.^2./na.^2)-1));
Sda= (((nf.^2-Nm.^2)./(Nm.*(ds+df+dc))).*((na.^2-nc.^2)./(nf.^2-nc.^2)).*((((Nm./nc).^2)+((Nm./na).^2)-1)./( ((Nm./nc).^2)+((Nm./nf).^2)-1))).^p;
plot(df,Snc)

 Réponse acceptée

KSSV
KSSV le 10 Fév 2022
l=633*(10)^(-9);
k0=(2*pi)/l;
nc=1.33;
na=1.43265;
nf=1.59;
nm=0.064+1i*4;
ns=1.49;
a=54:0.01:70 ;
df=linspace(1,300,length(a));
nf=1.59;
k0=(2*pi/633);
Nm=nf*sind(a);
p=1;
ds=((1-p)./(k0.*sqrt(Nm.^2-ns.^2)))+(p./((Nm./nf).^2+(Nm./ns).^2-1).*(k0.*sqrt(Nm.^2-ns.^2)));
dc=((1-p)./(k0.*sqrt(Nm.^2-nc.^2)))+(p./((Nm./nf).^2+(Nm./nc).^2-1).*(k0.*sqrt(Nm.^2-nc.^2)));
da=((1-p)./(k0.*sqrt(Nm.^2-na.^2)))+(p./((Nm./nf).^2+(Nm./na).^2-1).*(k0.*sqrt(Nm.^2-na.^2)));
Snc= ((nc./Nm).*((nf.^2-Nm.^2)./(nf.^2-nc.^2)).*(dc./(ds+df+dc)).*(2.*(Nm.^2./nc.^2)-1));
Sna= ((na./Nm).*((nf.^2-Nm.^2)./(nf.^2-na.^2)).*(da./(ds+df+da)).*(2.*(Nm.^2./na.^2)-1));
Sda= (((nf.^2-Nm.^2)./(Nm.*(ds+df+dc))).*((na.^2-nc.^2)./(nf.^2-nc.^2)).*((((Nm./nc).^2)+((Nm./na).^2)-1)./( ((Nm./nc).^2)+((Nm./nf).^2)-1))).^p;
plot(df,Snc)
Warning: Imaginary parts of complex X and/or Y arguments ignored.

8 commentaires

shiv gaur
shiv gaur le 10 Fév 2022
how we use zeros in this program
KSSV
KSSV le 10 Fév 2022
What zeros?
shiv gaur
shiv gaur le 10 Fév 2022
use of zeros of the df
KSSV
KSSV le 10 Fév 2022
Did you raise any question regarding use of zeros of df? What was your question and what you are expecting?
shiv gaur
shiv gaur le 10 Fév 2022
if you have idea of using zeros so pl help because I have use zeros in initial program
KSSV
KSSV le 10 Fév 2022
I know zero is represented by 0. How and why you want to use here?
shiv gaur
shiv gaur le 10 Fév 2022
for exaple this type of program example program for use of zeros for initialization
function kk1
clc;clear;close all;
l=633;
c = 1;
k0=2*pi/l;
ea=1.39;
da=1:300;
theta=1:70;
y=zeros(length(theta),length(da));
np=1.5;
x=(2*pi/l)*np*sind(theta);
function y=f(theta,da)
for i=1:length(theta)
iter = 0;
for j=1:length(da)
iter
ka=k0*sqrt(ea-x.^2);
f=(1-exp(2*1i.*da(j).*ka(i)))/(1+exp(2*1i.*da(j).*ka(i)));
%pfms=2*atan(1i*a.*b);
y(i,j)=2*atan(1i*c.*f);
% disp(y);
iter = iter + 1;
end
end
end
plot(da,y )
end
KSSV
KSSV le 10 Fév 2022
Jeez you want to use initilization?
If you are using a loop and filling values into it, you have to initalize the array using zeros.
If you are not using loop and getting the LHS by vectorization, no loop is needed.

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Plus de réponses (1)

0 votes

It seems there is a problem in Snc solution. ds and dc are vectors of 1601 elements whereas df has 300 elements.
Snc= ((nc/Nm).*((nf.^2-Nm.^2)./(nf.^2-nc.^2)).*(dc./(ds+df+dc)).*(2.*(Nm.^2./nc.^2)-1));
The same in Sna line:
Sna= ((na./Nm).*((nf.^2-Nm.^2)./(nf.^2-na.^2)).*(da./(ds+df+da)).*(2.*(Nm.^2./na.^2)-1));
I don't know the aim of df but try initializing the same length as ds.

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