Hello everybody I convert the numbers from 0 to 7 to binary like it’s shown here
N=8;
r=3
for N=0:1:N-1
A=dec2bin(N,r)
end
i have to calculate the XOR of each number(bit by bit)with 1=>A xor 1 i explain for 1 for example 1=0 0 1 I have to do 0 XOR 0 than the result which is 0 with the 3rd one(0 XOR 1) and the result with 1 i'm struggling please help me

 Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 29 Nov 2014
Modifié(e) : Azzi Abdelmalek le 29 Nov 2014

0 votes

N=8;
r=3
A=zeros(N,r)
out=zeros(N,1)
for k=0:1:N-1
A(k+1,:)=dec2bin(k,r)-'0'
out(k+1,1)=xor(xor(A(k+1,1),A(k+1,2)),A(k+1,3))
end
[A out]

2 commentaires

Dija
Dija le 29 Nov 2014
it doesn't work :/
Dija
Dija le 29 Nov 2014
Thank you So much

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