How to get Points(x,y) from function

hi everybody,

how can i get X,Y values from the following matlab-script?

X = @(t) 0.5 + 0.5*(((abs(cos(t))).^B)/cos(t))

Y = @(t) 0.5*T*(((abs(sin(t))).^B)/sin(t))*(1 - (0.5 + 0.5*(((abs(cos(t))).^B)/cos(t))).^P) + C*sin(((0.5 + 0.5*(((abs(cos(t))).^B)/cos(t))).^E * pi)) + R*sin((0.5 + 0.5*(((abs(cos(t))).^B)/cos(t)))*2*pi)

t = [0.01:0.01:2*pi]

B = 1.75

T = 0.18

P = 1.1

C = 0.11

E = 0.8

R = 0.0

fplot(X,Y)

As you can see in the attaches photo, I couldn't have then. I just could plot them

Answer 1

[Voss]

t = [0.01:0.01:2*pi]

t = 1×628

0.0100 0.0200 0.0300 0.0400 0.0500 0.0600 0.0700 0.0800 0.0900 0.1000 0.1100 0.1200 0.1300 0.1400 0.1500 0.1600 0.1700 0.1800 0.1900 0.2000 0.2100 0.2200 0.2300 0.2400 0.2500 0.2600 0.2700 0.2800 0.2900 0.3000

B = 1.75

B = 1.7500

T = 0.18

T = 0.1800

P = 1.1

P = 1.1000

C = 0.11

C = 0.1100

E = 0.8

E = 0.8000

R = 0.0

R = 0

X = @(t) 0.5 + 0.5*(((abs(cos(t))).^B)./cos(t))

X = function_handle with value:
    @(t)0.5+0.5*(((abs(cos(t))).^B)./cos(t))

Y = @(t) 0.5*T*(((abs(sin(t))).^B)./sin(t)).*(1 - (0.5 + 0.5*(((abs(cos(t))).^B)./cos(t))).^P) + C*sin(((0.5 + 0.5*(((abs(cos(t))).^B)./cos(t))).^E * pi)) + R*sin((0.5 + 0.5*(((abs(cos(t))).^B)./cos(t)))*2*pi)

Y = function_handle with value:
    @(t)0.5*T*(((abs(sin(t))).^B)./sin(t)).*(1-(0.5+0.5*(((abs(cos(t))).^B)./cos(t))).^P)+C*sin(((0.5+0.5*(((abs(cos(t))).^B)./cos(t))).^E*pi))+R*sin((0.5+0.5*(((abs(cos(t))).^B)./cos(t)))*2*pi)

fplot(X,Y)

X = X(t)

X = 1×628

1.0000 0.9999 0.9998 0.9997 0.9995 0.9993 0.9991 0.9988 0.9985 0.9981 0.9977 0.9973 0.9968 0.9963 0.9958 0.9952 0.9946 0.9939 0.9932 0.9925 0.9917 0.9909 0.9901 0.9892 0.9883 0.9873 0.9864 0.9853 0.9843 0.9832

Y = Y(t)

Y = 1×628

0.0000 0.0000 0.0000 0.0001 0.0001 0.0002 0.0003 0.0003 0.0004 0.0006 0.0007 0.0008 0.0009 0.0011 0.0013 0.0014 0.0016 0.0018 0.0021 0.0023 0.0025 0.0028 0.0031 0.0033 0.0036 0.0040 0.0043 0.0046 0.0050 0.0053

[Hasan Ballouk]

perfect, thank you very much!

[Voss]

You're welcome!