Three dimensional averages?

I have a data set that is 18x8x3, 18 mice completing a maze 3 times over 8 days. I need to calculate the average time for each mouse averaged over all 8 days and 3 trials on each of the 8 days. I'm kind of lost on how to do it. I started off with:

mouseavg= mean(mouse(1:18,:,:)); %where the data set is named 'mouse'

This code returned a 1x8x3 and i'm pretty sure it's not what i'm looking for, and I couldn't even really tell you what it is giving me. This is my first time working with three dimensions and I'm really struggling to wrap my brain around it.

As a bonus I need to print the fastest and slowest time and which mouse it came from. Any and all help appreciated. Thanks!

edit to ask: should I use some kind of for loop?

Answer 1

[AndresVar]

You can specify the dimension of averaging: Average or mean value of array - MATLAB mean (mathworks.com)

M = mean(A,dim)

M = mean(A,vecdim)

Then you can try

mouseavg = mean(mouse,[daysDim trialsDim])

Or you can reshape it so that all trials appear as columns: Reshape array - MATLAB reshape (mathworks.com)

mouse2=reshape(mouse,numberOfMice,[])
mouseavg = mean(mouse2,2);

[Lee]

Thank you! The mouseavg=mean(mouse,[daysDim trialsDim]) worked perfect!