how to extract a value with a specific character out of an character array
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
a great example to describe this would be for emails. Say we have an input of:
emails = 'someone, random@gmail, other'
how would one know to select the one with the @gmail and then add the .com to the end after?
If there are multiple emails in the array, only display the first one.
0 commentaires
Réponse acceptée
DGM
le 24 Fév 2022
Modifié(e) : DGM
le 24 Fév 2022
I'm not sure which extra emails should be rejected. I'm going to assume that all other emails get rejected
emails = {'someone, random@gmail, backupaccount@yahoo, other';
'someone else, random2@hotmail, other'};
mailhost = regexp(emails,'@[^,]*','match');
mailhost1all = [mailhost{1}{1} '.com']
If instead there might be more than one email per entry in the emails array, and you only want the first email per entry in the array:
mailhost1each = cell(numel(emails),1);
for acct = 1:numel(emails)
mailhost1each{acct} = [mailhost{acct}{1} '.com'];
end
mailhost1each
3 commentaires
Rik
le 24 Fév 2022
mailhost1each=strrep(mailhost1each,'@earthlink.com','@earthlink.net');
DGM
le 25 Fév 2022
Maybe something like this?
emails = {'someone, random@gmail, backupaccount@yahoo, other';
'someone else, random2@earthlink, other'};
% match the whole email address
mailaccounts = regexp(emails,'[^,\s]*?@[^,]*','match');
% these hosts should be .net
hasnettld = {'earthlink','comcast','airmail','charter'};
hasnettld = cellfun(@(x) ['@' x],hasnettld,'uniform',false);
firstmailaccounts = cell(numel(emails),1);
for acct = 1:numel(emails)
thisacct = mailaccounts{acct}{1};
if contains(thisacct,hasnettld)
firstmailaccounts{acct} = [thisacct '.net'];
else
firstmailaccounts{acct} = [thisacct '.com'];
end
end
firstmailaccounts
I'm sure this can be simplified, but I'm still not really sure what you want matched.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Startup and Shutdown dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!