Apply logical mask to every matrix in array
217 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have a 3D array of size 640x640x20 i.e. 20 matrices of size 640x640. In addition I have a logical mask of size 640x640. How can I apply this mask to every matrix in the array? Is this only possible with a for loop?
for jj=1:20
mat_temp=B(:,:,jj);
mat_temp(mask==1)=NaN
B(:,:,jj)=mat_temp;
end
%% I tried the following but it didn't worked (mask was only applied to first matrix)
B(mask==1)=NaN;
0 commentaires
Réponses (3)
Jan
le 24 Fév 2022
Modifié(e) : Jan
le 25 Fév 2022
B = reshape(1:24, 2,3,4);
mask = logical([1,0,1; 0,1,0]);
sB = size(B);
B = reshape(B, [], sB(3)); % Join the first two dimensions
B(mask, :) = NaN;
B = reshape(B, sB)
% Alternatively:
M = ones(size(mask));
M(mask) = NaN;
B = B .* M;
Note: No need to compare mask with 1: mask==1. Use mask directly, if it is a logical array.
2 commentaires
Jan
le 25 Fév 2022
A speed coparison with R2018b:
X = rand(640, 640, 20);
mask = rand(640, 640) > 0.6;
rep = 1e2;
B = X;
tic;
for k = 1:rep
for jj=1:20
mat_temp = B(:,:,jj);
mat_temp(mask==1) = NaN;
B(:,:,jj) = mat_temp;
end
end
toc % Elapsed time is 8.416893 seconds.
B = X;
tic;
for k = 1:rep
sB = size(B);
B = reshape(B, [], sB(3));
B(mask, :) = NaN;
B = reshape(B, sB);
end
toc % Elapsed time is 0.966218 seconds.
B = X;
tic;
for k = 1:rep
M = ones(size(mask));
M(mask) = NaN;
B = B .* M;
end
toc % Elapsed time is 1.173872 seconds.
B = X;
tic;
for k = 1:rep
s = size(B);
f = find(mask==1) + (0:s(3)-1) .* (s(1)*s(2));
B(f) = nan;
end
toc % Elapsed time is 2.992846 seconds.
David Hill
le 24 Fév 2022
s=size(B);
f=find(mask==1)+(0:s(3)-1).*(s(1)*s(2));
B(f)=nan;
0 commentaires
Loïc Reymond
le 29 Mai 2023
The most compact way would probably be:
bsxfun(@(x,y) x.*y,mat,mask)
Or alternatively (probably slower):
mat.*repmat(mask,1,1,size(mat,3))
Where mat is your 640x640x20 matrix and mask your masking array.
0 commentaires
Voir également
Catégories
En savoir plus sur Image Data Workflows dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!