How can I apply a logical mask to an image variable?
8 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
dila suay
le 24 Fév 2022
Commenté : Kaitlin Wang
le 24 Fév 2022
Hello,
I am trying to apply a logical mask to an image variable, however I couldnt manage to do it so far.
I have tried
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
Also, I've tried to apply mask to the rgbImage.CData directly. All of them are giving me errors. What else I can try?
Thank you so much
2 commentaires
Walter Roberson
le 24 Fév 2022
Your rgbImage is a handle to a deleted image() object -- not an array of data.
Réponse acceptée
Walter Roberson
le 24 Fév 2022
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
This cannot be an image() object unless you want to do something like
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
... but that would be directly on top of the old image.
2 commentaires
Walter Roberson
le 24 Fév 2022
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);
or
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);
Plus de réponses (1)
Image Analyst
le 24 Fév 2022
You don't need to do both of these:
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
All you need is the first one. Don't do the second one. It's not right and would need "fixing".
1 commentaire
Kaitlin Wang
le 24 Fév 2022
sir you are my hero. i have been looking at your answers for weeks and learning so much. thank you
Voir également
Catégories
En savoir plus sur Image Data Workflows dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!