how to remove columns from a 3D array, considering user input

4 vues (au cours des 30 derniers jours)
Hugo
Hugo le 25 Fév 2022
Modifié(e) : Jan le 25 Fév 2022
Hello,
I have a 3D matrix A, with dimensions 50*1000*30. I would like to remove some columns of the 30 I have (3rd dimension). The columns that I would like to have removed should be defined by user input, separated by commas. An example of an acceptable input is 1,5,7,9
for the removal of the columns 1, 5, 7 and 9 of all of the 50 tables. I know the input can be coded in something like this:
columns= input('Please write the number of the columns to be removed, separated by commas')
However, I don't know how I can obtain a new matrix, let's call it B, with the columns stated as input (variable columns) removed.
Any suggestions on how to do this?
I thank you in advance,
Best regards,

Réponse acceptée

Jan
Jan le 25 Fév 2022
Modifié(e) : Jan le 25 Fév 2022
Either use square brackets for the input:
b = input('Indices enclosed in square brackets: ');
% Type in: [1,5,7]
Or input a string and convert it manually:
s = input('Indices, comma separated: ', 's');
s = strrep(s, ',', ' ');
b = sscanf(s, '%d');
% b = [1,5,7]
Then:
A = rand(50, 1000, 30);
A(:, :, b) = [];
% Or do you mean the 1st dimension?
% A(b, :, :) = [];

Plus de réponses (0)

Catégories

En savoir plus sur Programming dans Help Center et File Exchange

Tags

Produits


Version

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by