How to remove repeated values mantaining the first one from an array ?

I have something like:

10000111111111011011100000111011000111111011000000010101011111111....

how to:

00000100000000010010000000100010000100000010000000000000010000000....

The second repetition makes the beggining of a series.

Answer 1

[Sean de Wolski]

 abs(diff('0000111001111101101'))

[Guillaume]

Hum, it looks like the OP only wants the transitions from 0 to 1 (which would be diff(x) > 0) but only when there's more than one consecutive 1 (which is not as simple unfortunately).

Answer 2

[Guillaume]

 s = '10000111111111011011100000111011000111111011000000010101011111111'
 o = char('0' + ([0 diff(s) > 0] & [~diff(s) 0]))