Root LP problem is unbounded.

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KRISHNA TEJA DUDE
KRISHNA TEJA DUDE le 1 Mar 2022
p = optimproblem;
x = optimvar('x', 2,'Type','integer','LowerBound',0,'UpperBound',Inf);
p.ObjectiveSense = 'maximize';
p.Objective = 10*x(1) + 20*x(2);
cons1 = 6*x(1) + 8*x(2) >= 48;
cons2 = x(1) + 3*x(2) >=12;
p.Constraints.cons1 = cons1;
p.Constraints.cons2 = cons2;
sol = solve(p);
sol.x
Output ----
Solving problem using intlinprog.
Root LP problem is unbounded.
Intlinprog stopped because the root LP problem is unbounded.
ans =
[]

Réponse acceptée

Torsten
Torsten le 1 Mar 2022
Yes, I can see it with my naked eye that you can make the objective function as big as you like.
Take x(1) = 1e100, x(2) = 1e100, then x is feasible and the objective gives 30*1e100.

Plus de réponses (1)

Janardhan Rao Moparthi
Janardhan Rao Moparthi le 28 Déc 2023
Since you do not specify the boundaries for the variable x(1) and x(2), it is giving error. instead try
  1. if the variables are not binary
lb = zeros(2,1);
ub = [inf;inf];
2.If the variables are binary
lb = zeros(2,1);
ub = [1;1];

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