Effacer les filtres
Effacer les filtres

How do I calculate the moment of force due to a load distribution or at least get a point of application?

11 vues (au cours des 30 derniers jours)
I have the following data where the X represents the physical coordenate and Y is the force value at that point.
I would like to calculate the moment of force at x=0.06 but I don´t see how to do it with Matlab.
The perfect solution for me would be divide the figure in 2 intervals [0 0.06] and [0.06 0.12] and calculate total force and the application point. The force is calculated using trapz function but i don't see how I can get the point of application.
Thanks

Réponses (1)

Johan
Johan le 2 Mar 2022
Modifié(e) : Johan le 2 Mar 2022
Assuming you have an XY array of data, dividing it in two part can be done by filtering the data against a chosen criteria:
XYdata = [linspace(1,10,8)',rand(8,1)]; % increasing X and random Y data
x_threshold = 5;
%filter the rows in column 1 that are more than x_threshold
XYdata(XYdata(:,1)>x_threshold,:) ;
%filter the rows in column 1 that are less than x_threshold
XYdata(XYdata(:,1)<x_threshold,:) ;
Then you can do your calculation on those filtered array.
  1 commentaire
Andriy Voshchenko
Andriy Voshchenko le 2 Mar 2022
Modifié(e) : Andriy Voshchenko le 2 Mar 2022
I have both arrays of data. Dividing the data isn´t a problem, i don´t know how to calculate the application point of the distribution of the forces in this case.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Programming dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by