- Do you expect 4 rows times 6 columns of boxes?
- Replace i by xx and ii by yy or something associated with directions
- Set the axes limits before adding the boxes. It's confusing that the limits change all the time
- And format the code properly. (I did it this time.)
Looping through cell array in order
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I'm drawing squares on a grid. The squares need to have an ID as set within a cell array. I was expecting the ID to loop through each ID in the cell in order by instead it cycles through in rows.

 
cell_id = cell(1, 2); % 1 x 5 cell array
cell_id{1, 1} = 1365;
cell_id{1, 2} = 1256;
cell_id{1, 3} = 6214;
cell_id{1, 4} = 2587;
cell_id{1, 5} = 1564;
hold on
for i = 1:2:12
count = 1;
for ii = 1:2:12
plot(1*i , 1*ii, 's', 'MarkerSize', 50);
if (count <= 5)
id = cell_id(1,count);
text(1*i, 1*ii, ['ID:',id]);
count = count + 1;
elseif (count > 5)
id = cell_id(1,1);
count = 1;
text(1*i, 1*ii, ['ID:',id]);
end
end
end
Any ideas, thanks.
1 commentaire
per isakson
le 10 Déc 2014
Modifié(e) : per isakson
le 10 Déc 2014
Réponse acceptée
Guillaume
le 10 Déc 2014
You appear to be a bit confused about a few things:
cell_id = cell(1, 2);
declares a 1 x 2 cell array, not a 1 x 5. Anyway, you could replace your first two lines with:
cell_id = {1365, 1256, 6214, 2587, 1564};
Secondly, you reset your count for each column, since it's set to one in the first for loop. You probably meant to do the assignment to 1 before the first loop.
Also, use more descriptive variables than i and ii. row and col would be better.
To sum it up:
figure; axis off; hold on;
cell_id = {1365, 1256, 6214, 2587, 1564};
count = 1;
for col = 1:2:12
for row = 1:2:12
plot(col, row, 's', 'MarkerSize', 50);
text(col, row, sprintf('ID:%d', cell_id{count}));
count = mod(count, numel(cell_id)) + 1;
end
end
7 commentaires
Image Analyst
le 11 Déc 2014
I see no reason for a cell array at all. What about this requires cells instead of a simple numerical array?
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Graphics Performance dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
