Update matrix A so that all odd values will be subtracted by 1
A=[1 2 3;4 5 6; 4 5 2]
A = 3×3
1 2 3 4 5 6 4 5 2
rem(A,2)-1%WRONG
ans = 3×3
0 -1 0 -1 0 -1 -1 0 -1

 Réponse acceptée

Arif Hoq
Arif Hoq le 8 Mar 2022
Modifié(e) : Arif Hoq le 8 Mar 2022
A=[1 2 3;4 5 6; 4 5 2]
A = 3×3
1 2 3 4 5 6 4 5 2
B=rem(A,2) % returns the odd number
B = 3×3
1 0 1 0 1 0 0 1 0
output=A-B
output = 3×3
0 2 2 4 4 6 4 4 2

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