Storing values in a matrix
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Mohammed Rabani
le 9 Mar 2022
Réponse apportée : Peter Perkins
le 9 Mar 2022
Hi,
I have a code which finds the daily average from the hourly values and stores them in a variable. I want to store this values in a matrix so I can use them elsewhere later. Please let me know.
for column = 2:width(cooling_load)
x = table2array(cooling_load(:,column));
for i = 0:364
for j=1:24
sumof =sumof + x(i*24+j+2,1);
end
avgg = sumof/24;
sumof=0;
daily(i+1)=avgg;
end
coolingload = daily'
end
4 commentaires
Rik
le 9 Mar 2022
You already know how to index, so what is your question? You already know how to store values in an array based on the loop variable.
Réponse acceptée
Rik
le 9 Mar 2022
You're already there:
for column = 2:width(cooling_load)
x = table2array(cooling_load(:,column));
for i = 0:364
sumof=0;
for j=1:24
sumof =sumof + x(i*24+j+2,1);
end
avgg = sumof/24;
daily(i+1,column-1)=avgg;
% ^^^^^^^^
% just this simple change
end
end
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Peter Perkins
le 9 Mar 2022
This will be MUCH easier using a timetable. It's a one-liner:
>> tt = timetable(rand(100,1),'RowTimes',datetime(2022,3,9,1:100,0,0))
tt =
100×1 timetable
Time Var1
____________________ ________
09-Mar-2022 01:00:00 0.697
09-Mar-2022 02:00:00 0.40754
[snip]
13-Mar-2022 03:00:00 0.089853
13-Mar-2022 04:00:00 0.16103
>> ttDaily = retime(tt,'daily','mean')
ttDaily =
5×1 timetable
Time Var1
___________ _______
09-Mar-2022 0.56102
10-Mar-2022 0.43778
11-Mar-2022 0.49814
12-Mar-2022 0.57098
13-Mar-2022 0.43989
At this point, you can get the means from that daily timetable ...
>> dailyMeans = ttDaily.Var1
dailyMeans =
0.56102
0.43778
0.49814
0.57098
0.43989
... but I doubt you need to. Just leave them there, along with their dates.
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