Conversion of a binary matrix to decimal matrix

5 vues (au cours des 30 derniers jours)
Mehmet
Mehmet le 14 Mar 2022
Commenté : Mehmet le 14 Mar 2022
Hello everyone,
I wonder if there is an easier way to convert a binary matrix to a decimal matrix?
For example: A = [1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0; 0 0 0 0 1 1 1 1 1 1 1 1 0 0 0 0] (2x16 matrix) will be converted into B = [255 0; 15 240] (2x2 matrix). So, 8 bit binary numbers in the original matrix will be converted into decimal numbers. Or, in general, an Mx8N binary matrice will be converted into an MxN decimal matrice.
I know i can do it by using for loops and binaryVectorToDecimal or bi2de functions.
However, there might be a more easier way to do it by utilizing another built-in functions.
Thanks in advance,

Réponse acceptée

Stephen23
Stephen23 le 14 Mar 2022
Modifié(e) : Stephen23 le 14 Mar 2022
The most efficient approach would probably be to avoid type conversion (e.g. to character) and to avoid BIN2DEC.
It is just as easy to do the whole thing with basic numeric operations:
A = [1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0;0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,0]
A = 2×16
1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 0 0 0 0
M = reshape(pow2(7:-1:0)*reshape(A.',8,[]),[],size(A,1)).'
M = 2×2
255 0 15 240
  2 commentaires
Jan
Jan le 14 Mar 2022
Modifié(e) : Jan le 14 Mar 2022
This is 5 times faster than the bin2dec approach.
To my surprise 2.^(7:-1:0) is faster than pow2(7:-1:0).
Mehmet
Mehmet le 14 Mar 2022
Thanks. This is so cool!

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Plus de réponses (1)

Matt J
Matt J le 14 Mar 2022
Modifié(e) : Matt J le 14 Mar 2022
A = [1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0;0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,0];
e=kron(speye(2),2.^(7:-1:0)');
B = A*e
B = 2×2
255 0 15 240

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