Replace string values in a table
71 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
James Bishop
le 16 Mar 2022
Réponse apportée : Eric Sofen
le 17 Mar 2022
I have a column in a table with 3 wine types defined as character values "1", "2" and "3". I want to replace these values with "French", "Spanish" and "Italian" respectively. I am treating the column as an array of strings and using the tried and trusted combination of a for loop and if/elseif ladder to select and replace each of the string values in the table. Howver, when I run this in the command window, I get an error saying 'Unable to perform assignment because the left and right sides have a different number of elements' . My code is listed below and the array I am trying run it on is attached.
for i = 1:size(Typ)
if((Typ(i))=="1")
Typ(i)="French"
elseif((Typ(i))=="2")
Typ(i)="Spanish"
elseif((Typ(i))=="3")
Typ(i)="Italian"
else
end
end
0 commentaires
Réponse acceptée
Mathieu NOE
le 16 Mar 2022
hello
my 2 cents suggestion
Typ = readtable('Typ.csv');
Typ = table2array(Typ);
for i = 1:numel(Typ)
if((Typ(i))== 1)
newTyp{i,1}='French';
elseif((Typ(i))==2)
newTyp{i,1}='Spanish';
elseif((Typ(i))==3)
newTyp{i,1}='Italian';
else
end
end
Typ = newTyp;
0 commentaires
Plus de réponses (2)
Eric Sofen
le 17 Mar 2022
This is what categorical is built for! When you create the categorical, you can specify the data, value set, and category names.
T = readtable("https://www.mathworks.com/matlabcentral/answers/uploaded_files/929319/Typ.csv");
T.Typ = categorical(T.V1, 1:3, ["French", "Spanish","Italian"])
0 commentaires
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!