How to plot a road along its height.
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Actually the data I have has latitude(x) and longitude(y) of a road and also I have height of the road (z). Now I want to construct a plot which has shows height too and that height should be color coded. How can I do that ?
2 commentaires
Sam Chak
le 21 Mar 2022
Are you trying to plot a top view of the roads and indicate the height of each road?

Muhammad Qaisar Fahim
le 21 Mar 2022
Réponse acceptée
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Sam Chak
le 21 Mar 2022
I guess you want to show something like this. Because the data is dense, it is not recommended to show the height of every point. But you can definitely adjust how and which particular point/region that you want to show the heights.
plot(A, B)
for t = 1:4379:numel(A)
text(A(t) + 0.0001, B(t) + 0.0001, ['(',num2str(C(t)),')'])
end

7 commentaires
Muhammad Qaisar Fahim
le 21 Mar 2022
Sam Chak
le 21 Mar 2022
Okay, I'm trying to figure out what you want. The spatial data latitude and longitude indicate the position of each point on a 2D surface. Then you want the color gradient to represent the elevation of each point, isn it?

Muhammad Qaisar Fahim
le 21 Mar 2022
Sam Chak
le 21 Mar 2022
I converted the longitude, latitude, elevation to Cartesian coordinates, and then used @KSSV's suggested code to plot it. Is this what you want?
x = C.*cos(B).*cos(A);
y = C.*cos(B).*sin(A);
z = C.*sin(B);
col = x; % This is the color, vary with x in this case.
surface([x x],[y y],[z z],[col col],...
'facecol','no',...
'edgecol','interp',...
'linew',2);

Sam Chak
le 21 Mar 2022
Wait. I think you need to consider the Earth radius (6371 km) in order to project the location of the points on the curved surface in Cartesian coordinates.
And then at each point, you want to show the elevation in the C.mat data using the color gradient. I think the z coordinate in not needed.
x = (6371).*cos(B).*cos(A);
y = (6371).*cos(B).*sin(A);
z = (6371).*sin(B);

Sam Chak
le 21 Mar 2022
Is the road curved? We need you to confirm.
x = (6371).*cos(B).*cos(A);
y = (6371).*cos(B).*sin(A);
scatter(x, y)

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