How to shuffle rows in pairs?

3 vues (au cours des 30 derniers jours)
Neuro
Neuro le 23 Mar 2022
Commenté : Neuro le 23 Mar 2022
Hello. I have a 600 x 1 matrix. They can have only 8 values, let's say 1, 2, 3, 4, 5, 6, 7, and 8. I want to randomize the order of the rows but in pairs so 1 is always followed by 2, and 3 is always followed by 4, 5 is always followed by 6, and 7 is always followed by 8. Like there were only 4 elements: 1-2, 3-4, 5-6, and 7-8. But in pairs in rows (within the same column).
One case: if we have
1
2
3
4
5
6
7
8
One of the many randomizations would be:
5
6
1
2
7
8
3
4
Thank you!
  2 commentaires
Image Analyst
Image Analyst le 23 Mar 2022
I don't understand how the 600 and 8 relate to each other. So do the numbers 1-8 repeat each other for rows 9-16, 17-24, etc. up to 593-600? Do you want the shuffling to occur totally within the band, like rows 1-8 must still be in rows 1-8 and rows 593-600 must still be in rows 593-600? Or can any row end up anyplace except that the following row must also be moved so that it's following it in its new row location?
Neuro
Neuro le 23 Mar 2022
Sorry. 600 is the number of rows and the integers 1 to 8 are the elements - they repeat each other. I need to shuffle the elements so they are shuffled in pairs so the element 2 is always preceeded by a 1, the 4 is always preceded by a 3, and so on. Like shuffling in pairs.

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Réponses (2)

Stephen23
Stephen23 le 23 Mar 2022
Modifié(e) : Stephen23 le 23 Mar 2022
V = 1+mod(0:599,8).' % fake data
V = 600×1
1 2 3 4 5 6 7 8 1 2
M = reshape(V,2,[]);
X = randperm(size(M,2));
V = reshape(M(:,X),[],1)
V = 600×1
1 2 7 8 3 4 5 6 5 6

Arif Hoq
Arif Hoq le 23 Mar 2022
Modifié(e) : Arif Hoq le 23 Mar 2022
try this:
A=randi([1 8],600,1);
for i=1:size(A,1)
if A(i)==1
A(i+1)=2;
elseif A(i)==3
A(i+1)=4;
elseif A(i)==5
A(i+1)=6;
elseif A(i)==7
A(i+1)=8;
end
end
  4 commentaires
Jan
Jan le 23 Mar 2022
I'm not sure what the purpose of your code is. A shorter version:
for i = 1:size(A,1)
if A(i) < 8
A(i+1) = A(i) + 1;
end
end
This might append an element and is not a random shuffling.
Neuro
Neuro le 23 Mar 2022
Thanks, but it doesn't work. It shuffles things without following the rule (pairs of rows) and it adds one more element to the end.

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