Making a spherical cap using equations of sphere
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Chris Dan
le 24 Mar 2022
Réponse apportée : Chris Dan
le 29 Mar 2022
Hello everyone,
I am trying to make a spherical cap using points or nodes and mesh grid . I dont want to use built in functions. I am having some problems. Here is my code
% plotting script
% select : which plot you want
set(groot,'defaultLegendInterpreter','latex');
set(0, 'DefaultFigureRenderer','painters');
set(0, 'DefaultFigureRenderer', 'OpenGL');
set(groot,'defaultAxesTickLabelInterpreter','latex');
set(groot,'defaulttextInterpreter','latex');
%%
% Plot the sphere or spherical patch
p = linspace(-1/2,1/2,10);
radius_1 = p(size(p,2))/2;
radius_2 = radius_1 /2;
[X,Y,Z] = meshgrid(p,p,p);
theta= atan(Y./X);
active = (X.^2+Y.^2 +Z.^2 <= radius_1);
active_2 = (X.^2+Y.^2 +Z.^2 <= (radius_1 -radius_2)) ;
figure()
plot3(X(active),Y(active),Z(active),'o','MarkerFaceColor','red');
hold on
plot3(X(active_2),Y(active_2),Z(active_2),'o','MarkerFaceColor','cyan');
I cannot draw the spherical cap. I have the thetha but how do i use it to cut the sphere to make spherical cap and i want to know which nodes are inside the cap and which are outside the cap using mesh grid.
Does anyone knows how to do it?
1 commentaire
Bruno Luong
le 24 Mar 2022
X.^2+Y.^2 +Z.^2 is the square of the distance to origin, then you compare with radius and diffderence of radius, it does noot make any interpretable sense to me.
Réponse acceptée
Bruno Luong
le 24 Mar 2022
phi=linspace(pi/2,pi/6,30); % the cap end is determined by pi/6 change accordinglt
theta=linspace(0,2*pi,120);
r=3;
[PHI,THETA]=meshgrid(phi,theta);
X=r*cos(THETA).*cos(PHI);
Y=r*sin(THETA).*cos(PHI);
Z=r*sin(PHI);
surf(X,Y,Z)
axis equal;
8 commentaires
Bruno Luong
le 24 Mar 2022
Sorry I don't understand what you ask for.
And in your last code you are still compare distance squared with radius without squared.
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