How to interchange elements of an array?

X = [ 4 2 3 6 5 1]

x1 = [2 3 1 2]

I want to interchange entries of X based on x1, that is

Output X =[4 6 2 3 5 1];

Any help is appreciated.

Answer 1

[Voss]

X = [  4     2     3     6     5     1];
x1 = [2 3 1 2];

Xnew = X;
for ii = 1:numel(x1)
    Xnew([ii x1(ii)]) = Xnew([x1(ii) ii]);
end
Xnew

Xnew = 1×6

4 6 2 3 5 1

[Noor Fatima]

@_Thank you, Is it possible without loop?

[Voss]

Well, you can write down an expression to do it in this particular case:

X = [  4     2     3     6     5     1];
Xnew = X([1 4 2 3 5 6])

Xnew = 1×6

4 6 2 3 5 1

But I don't think you can do it in general without using a loop somewhere, because the result of any swap depends on the results of the previous swaps, so it's necessarily an iterative process.