I want to take time derivative of the function
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Haseeb Hashim
le 29 Mar 2022
Modifié(e) : Walter Roberson
le 15 Août 2022
syms theta(t)
theta2 = 0:0.001:2*pi;
r_x = 11.6;
r_y = 4.3;
r2 = 3.5;
omega2 = 17; % Given in RPM
omega2 = omega2*2*pi/60; % In rad/s
link3_linear = sqrt((r_x - r2*cos(theta)).^2 + (r_y - r2*sin(theta).^2));
dr3 = diff(link3_linear,t,1);
Now I have this code but how can we get the numerical answer by substituting for theta dot which comes as a result of the derivative with time 3 we can use the subs function but what are we substituting for or what would be the theta dot interpretation in MATLAB
I hope you understand my question
I just want the velocity of link3_linear by taking it sderivative and then substituting the angular velocity theta dot in the resulting derivative
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