Convert char to cell
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I want to intruduce data in a table but when i run the program it says that conversion to cell from char is not possible. Did someone knows what is wrong in this code?
ze1.Nome(end+1)=input('Introduza o seu nome: ', 's');
ze1.Aperlido(end+1)=input('Introduza o seu apelido: ','s');
ze1.Categoria(end+1)=input('Introduza a sua categoria(Aluno, Docente ou Feuncionário): ','s');
ze1.Numero(end+1)=input('Introduza o seu numero: ','s');
ze1.Mail(end+1)=input('Introduza o seu e-mail: ','s');
ze1.Telefone(end+1)=input('Introduza o seu nº de telefone: ','s');
Thank you all
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David Young
le 30 Déc 2014
Modifié(e) : David Young
le 30 Déc 2014
Assuming that ze1.Nome is already a cell array, all you need to do is to replace the round brackets used for indexing it with curly brackets. This then assigns the string to the contents of a cell, rather than trying to convert the string to a cell. Like this:
ze1.Nome{end+1} = input('Introduza o seu nome: ', 's');
and the same for the other fields.
You should also consider changing the way you store the data. Instead of having a scalar struct with a cell array stored at each field, you could have a struct array with a string stored at each field. Then the line above would be
ze1(end+1).Nome = input('Introduza o seu nome: ', 's');
which may simplify some later processing. However, there will need to be changes earlier in the program to set the array up consistently with this.
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Azzi Abdelmalek
le 30 Déc 2014
ze1=struct('Nome',[],'Aperlido',[],'Categoria',[],'Numero',[],'Mail',[],'Telefone',[]) ze1.Nome{end+1}=input('Introduza o seu nome: ', 's'); ze1.Aperlido{end+1}=input('Introduza o seu apelido: ','s'); ze1.Categoria{end+1}=input('Introduza a sua categoria(Aluno, Docente ou Feuncionário): ','s'); ze1.Numero{end+1}=input('Introduza o seu numero: ','s'); ze1.Mail{end+1}=input('Introduza o seu e-mail: ','s'); ze1.Telefone{end+1}=input('Introduza o seu nº de telefone: ','s');
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