matlab code for python script?
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asim asrar
le 31 Mar 2022
Réponse apportée : Paras Gupta
le 22 Sep 2023
i am trying to write a matlab code for python script as:
class structure:
def __init__(self, shape, eps, mu):
self.shape = shape
self.eps = eps
self.mu = mu
self.epsr = np.ones(shape, dtype='float64')
self.mur = np.ones(shape, dtype='float64')
class Sphere(structure):
def __init__(self, shape, center, R, eps, mu, smoothing = False):
super(Sphere, self).__init__(shape, eps, mu)
self.center = center
self.R = R
self.smoothing = smoothing
self.get_epsr()
def get_epsr(self):
x = np.arange(self.shape[0])
y = np.arange(self.shape[1])
z = np.arange(self.shape[2])
X,Y,Z = np.meshgrid(x,y,z)
self.r = np.sqrt((self.center[1]-X)**2 + (self.center[0]-Y)**2 + (self.center[2]-Z)**2)
self.region = np.where(self.r >= self.R, 0, 1)
print("self.region value: ",self.region)
print("self.region shape: ",self.region.shape)
self.epsr += self.region * (self.eps - 1)
if self.smoothing == True:
smoothing_region = 1 - (np.where((0 < (self.r - self.R)) & ((self.r - self.R) < 1), 1/3*(self.r+np.sqrt(self.r**2-1)-2*self.R)**2, 1))
self.epsr += smoothing_region * (self.eps - 1)
del self.r
the call for these structures in python is as:
um = 1e-6
dx = 4.8 * um
lamb = 74.9*um
eps = np.zeros((250,250))
str1 = Sphere(shape = (250,250,250), center = (125,125,125), R = lamb*3/dx, eps=10, mu=1)
THE MATLAB SCRIPT WHICH I TRIED IS AS:
shape = [250,250,250]
N1=shape(1);
N2=shape(2);
N3=shape(3);
um = 1e-6
c = 3e8 % m/s
dx = 4.8 * um
dy = 4.8 * um
dz = 4.8 * um
dt = 1/4 * dx / c
lamb = 74.9*um
R = lamb*3/dx;
eps=10;
mu=1;
x = linspace(0,N1-1,N1);
y = linspace(0,N2-1,N2);
z = linspace(0,N3-1,N3);
[X,Y,Z] = meshgrid(x,y,z);
X=(X(:))';
Y=(Y(:))';
Z=(Z(:))';
center = [125, 125,125];
r = sqrt((center(2)-X).^2 + (center(1)-Y).^2 + (center(3)-Z).^2);
epsr = ones(shape);
mur = ones(shape);
for k=1:1:length(r)
for j = 1:1:length(r)
for k=1:1:length(r)
if r(:,:,k) >= R
epsr(:,:,k) =
Q: i am struck with implementation of region in matlab, can someone help me with this
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Réponse acceptée
Paras Gupta
le 22 Sep 2023
Hi Asim,
I understand that you want to convert the given python code to MATLAB.
In the given Python code, the “region” variable is calculated using np.where(self.r >= self.R, 0, 1). This condition sets the value of region to 0 where self.r >= self.R and 1 otherwise.
To implement this in MATLAB, you can use logical indexing as shown below:
shape = [250,250,250];
N1=shape(1);
N2=shape(2);
N3=shape(3);
um = 1e-6;
c = 3e8; % m/s
dx = 4.8 * um;
dy = 4.8 * um;
dz = 4.8 * um;
dt = 1/4 * dx / c;
lamb = 74.9*um;
R = lamb*3/dx;
eps=10;
mu=1;
x = linspace(0,N1-1,N1);
y = linspace(0,N2-1,N2);
z = linspace(0,N3-1,N3);
[X,Y,Z] = meshgrid(x,y,z);
% X=(X(:))';
% Y=(Y(:))';
% Z=(Z(:))';
center = [125, 125,125];
r = sqrt((center(2)-X).^2 + (center(1)-Y).^2 + (center(3)-Z).^2);
epsr = ones(shape);
mur = ones(shape);
region = zeros(size(r));
region(r >= R) = 0;
region(r < R) = 1;
epsr = ones(shape);
epsr = epsr + region * (eps - 1);
smoothing = false;
% Calculate smoothing_region
smoothing_region = zeros(size(r));
if smoothing==true
temp = (0 < (r - R)) & ((r - R) < 1);
smoothing_region(temp) = 1/3 * (r(temp) + sqrt(r(temp).^2 - 1) - 2 * R).^2;
end
% Update epsr with smoothing_region
epsr = epsr + smoothing_region * (eps - 1);
You can refer to the following documentation on array indexing for more information on the use of logical indexing.
Hope this helps.
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