Need help with If statement

Hello everyone, My question is, in the below code, idsabs can take any value from 1 to 16. Depending on the value of idsabs, i want to set the value of idcabs. Is there any other way of doing this, because i think its too long just to get a single value. Thank you so much and Happy New Year.

         if idsabs>=1 && idsabs<=2
              idcabs=1;
          elseif idsabs>=3 && idsabs<=4
              idcabs=3;
          elseif idsabs>=5 && idsabs<=6
              idcabs=4;
          elseif idsabs>=7 && idsabs<=8
              idcabs=6;
          elseif idsabs>=9 && idsabs<=10
              idcabs=5;
          elseif idsabs>=11 && idsabs<=12
              idcabs=7;
          elseif idsabs>=13 && idsabs<=14
              idcabs=8;
          elseif idsabs>=15 && idsabs<=16
              idcabs=2; 
          end

[Stephen23]

You define, for example, what happens for values of idsabs<=2 and idsabs>=3 , but what happens if idsabs is equal to 2.5 ?

[Aftab Ahmed Khan]

Hi Stephen, idsabs will take only whole numbers between 1 to 16. No decimal values.

[Jan]

If you have checked for idsabs<=2, there is no reason to check "idsabs>=3" anymore.

Answer 1

[Stephen23]

If adsabs only has whole values, then you could simply use a look-up table:

vec = [1,3,4,6,5,7,8,2];
adcabs = vec(ceil(adsabs/2));

This produces exactly the same values for adcabs as your questions gives:

>> arrayfun(@(x) vec(ceil(x/2)), 1:16)
ans = [1  1  3  3  4  4  6  6  5  5  7  7  8  8  2  2]

If you can tell us something about how the order of adcabs was generated, then maybe we could come up with a small function instead.

[Aftab Ahmed Khan]

Thank you for your help. Its done.

Answer 2

[Jan]

A little bit simpler without "compression" of the look-up-table:

LUT    = [1, 1, 3, 3, 4, 4, 6, 6, 5, 5, 7, 7, 8, 8, 2, 2];
idcabs = LUT(idsabs);