Parfor loops skipping an index
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When I run the piece of code below, the result shows that there is an index that is not executed...
temp=struct('myfield1',num2cell(ones(2,6)));
parfor i = 1:6
temp(2,i).myfield1 = i*4;
temp(2,i).myfield2 = i;
end
I have run this on a few computers and one of the index is always not executed (or at least seems to). For example, I could have temp(2,6).myfield1=1 and temp(2,6).myfield2=[] instead of temp(2,6).myfield1=24 and temp(2,6).myfield2=6.
Could it be because I did not define all the fields beforehand?
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Edric Ellis
le 6 Jan 2015
Yes, defining all the fields of temp beforehand works around this problem, like so:
temp=struct('myfield1',num2cell(ones(2,6)), 'myfield2', []);
parfor i = 1:6
temp(2,i).myfield1 = i*4;
temp(2,i).myfield2 = i;
end
% Assertions:
assert(isequal(4:4:24, [temp(2, :).myfield1]));
assert(isequal(1:6, [temp(2, :).myfield2]));
2 commentaires
Edric Ellis
le 6 Jan 2015
I'm afraid I know of no other workaround involving structures. Could you perhaps return cell arrays of data with which you can recreate the structure outside the PARFOR loop?
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