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Converge a 1x30 row vector to a 3x10 matrix

4 vues (au cours des 30 derniers jours)
Wietze Zijpp
Wietze Zijpp le 5 Avr 2022
Commenté : Voss le 6 Avr 2022
Suppose I have the following
z = [1:30]
Now I want to create a 3x 10 matrix. Where the entries in the first row are the first 10 values. In the second row entries 11:20 and in the third row 21:30

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Wietze Zijpp
Wietze Zijpp le 5 Avr 2022
Modifié(e) : Torsten le 5 Avr 2022
I have found the solution
Use
mymat = reshape(z,3,10)
  1 commentaire
Voss
Voss le 6 Avr 2022
"the entries in the first row are the first 10 values. In the second row entries 11:20 and in the third row 21:30"
If you want the order like that, you have to do it differently:
z = 1:30;
mymat = reshape(z,3,10)
mymat = 3×10
1 4 7 10 13 16 19 22 25 28 2 5 8 11 14 17 20 23 26 29 3 6 9 12 15 18 21 24 27 30
mymat = reshape(z,10,3).'
mymat = 3×10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

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